16x^2=2+4x

Solution for 16x^2=2+4x equation:

16x^2=2+4x

We move all terms to the left:

16x^2-(2+4x)=0

We add all the numbers together, and all the variables

16x^2-(4x+2)=0

We get rid of parentheses

16x^2-4x-2=0

a = 16; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·16·(-2)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*16}=\frac{-8}{32}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*16}=\frac{16}{32}
=1/2
$